November 01, 2007

psat problem

(x+y)^2-(x-y)^2 = 84

if x and y are both positive integers
what is the sum of x+y?

a)10
b) 12
c) 14
d) 16

(i think those were the answer choices...but don't quote me on it...)

6 comments:

Cadd said...

Are you freaking kidding me? Tell me when, in this life time will you ever have to do a math question like this (besides the SATs, GMAT, etc.).

Cadd said...

If this were on my exam, I'd pick C.

My reasoning? Here's what I do on the M/C portion of the CPA exams.

When I'm stuck on a question, I look for "power words" such as: all, always, never, only. Those are mostly likely not the answer.

Then I look at the other choices and see which one is longer. Normally I'd pick the longest answer choice. If they're almost equal in length, I stick with C.

=)

Now, do you really want me to do your taxes?

Cadd said...

I'm just baffled!

If I had to face a something like this in real life, I would google it. And guess what? BAM!! Here's the answer:

Use the difference of squares formula, a^2 - b^2 = (a + b)(a - b)

(x+y)^2 - (x-y)^2 = (x+y+x-y)(x+y-x+y) = 2x*2y = 84
xy = 21
Since x and y are given to be positive integers, only 1 and 21 or 3 and 7 will work. 22 is not one of the choices, so the answer is x+y = 10.

Cadd said...

I found out how to do this without cheating with google:

(x+y)^2-(x-y)^2 = 84

[(x+y)(x+y)]-[(x-y)(x-y)]=84

Let's remember our friend "FOIL"

(x^2+xy+xy+y^2)-(x^2-xy-xy+y^2)=84

cancel out the like terms

the x^2 & y^2 cancels each other out, right?

that leaves you with
xy+xy+xy+xy=84
that's 4xy = 84
xy = 21

DAMN, that was too much thinking!

VVN said...

Aahahahah...I check the blog and suddenly have 4 comments!

This was actually one of Maggie's PSAT questions. She asked me, I had no idea, so I posted it.

I had totally forgotten about foiling! I had to consult a math guru, who basically told me what you wrote on your 4th comment.

Cadd said...

Why would someone need to do this at a tender age of 16? I just don't get it.